1992 United States presidential election in Rhode Island

1992 United States presidential election in Rhode Island

November 3, 1992
Turnout76.6% 6.4 pp
 
Nominee Bill Clinton George H. W. Bush Ross Perot
Party Democratic Republican Independent
Home state Arkansas Texas Texas
Running mate Al Gore Dan Quayle James Stockdale
Electoral vote 4 0 0
Popular vote 213,299 131,601 105,045
Percentage 47.04% 29.02% 23.16%


President before election

George H. W. Bush
Republican

Elected President

Bill Clinton
Democratic

The 1992 United States presidential election in Rhode Island took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Rhode Island was won by Governor Bill Clinton (D-Arkansas) with 47.04% of the popular vote over incumbent President George H. W. Bush (R-Texas) with 29.02%. Businessman Ross Perot (I-Texas) finished in third, with 23.16% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush.