1940 United States presidential election in Kansas
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All 9 Kansas votes to the Electoral College | ||||||||||||||||||||||||||
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County Results
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| Elections in Kansas |
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The 1940 United States presidential election in Kansas took place on November 5, 1940, as part of the 1940 United States presidential election. Voters chose nine representatives, or electors, to the Electoral College, who voted for president and vice president.
Kansas was won by Wendell Willkie (R–New York), running with Minority Leader Charles L. McNary, with 56.86 percent of the popular vote, against incumbent President Franklin D. Roosevelt (D–New York), running with Secretary Henry A. Wallace, with 42.40 percent of the popular vote. This was the first time since 1896 that Kansas voted for a losing candidate, and the first time since 1884 that the state backed a losing Republican in a presidential election.
With 56.86 percent of the popular vote, Kansas would prove to be Willkie's third strongest state in the 1940 election in terms of popular vote percentage after South Dakota and neighboring Nebraska.