1900 United States presidential election in Pennsylvania

1900 United States presidential election in Pennsylvania
	November 6, 1900
McKinley 40–50% 50–60% 60–70% 70–80%	Bryan 40–50% 50–60% 60–70%
President before election; William McKinley; Republican	Elected President ; William McKinley; Republican

The 1900 United States presidential election in Pennsylvania, took place on November 6, 1900, as part of the 1900 United States presidential election. Voters selected 32 representatives, or electors to the Electoral College, who voted for president and vice president.

Pennsylvania voted for the Republican nominee, President William McKinley, over the Democratic nominee, former U.S. Representative and 1896 Democratic presidential nominee William Jennings Bryan. McKinley won Pennsylvania by a landslide margin of 24.31% in this rematch of the 1896 United States presidential election. The return of economic prosperity and recent victory in the Spanish–American War helped McKinley to score a decisive victory.

With 60.74% of the popular vote, Pennsylvania was McKinley's fourth-strongest victory in terms of percentage in the popular vote following Vermont, North Dakota and Maine.

Bryan previously lost Pennsylvania to McKinley four years earlier and would later lose the state again in 1908 to William Howard Taft.